Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: Rakkoonn on May 31, 2007, 03:02:44 AM
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I'm trying to figure out the mechanism of the following reaction:
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fi38.photobucket.com%2Falbums%2Fe129%2FSowaSowa%2Fcoum01.gif&hash=c1b4d4951f0399c6a0a54b39adf23ecfcce814c6)
I was told that it's a Knoevenagel condensation in the first step and then a cyclisation occurs. If I apply this scheme to my reaction it will look like this:
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.organic-chemistry.org%2Fnamedreactions%2Fknoeve3.gif&hash=d8ea8f7afa6da12ec1b3706746ac3a13f9ea4af1)
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fi38.photobucket.com%2Falbums%2Fe129%2FSowaSowa%2Fcoum02.gif&hash=796364e447d3989818563af927b30ac00c562620)
It doesn't look right. How does the cyclisation go?
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It is not Knoevenagel condensation, it is just simply an aldol condensation.
O O O O O
ll ll ll ll ll
R - C - H + HO - C - C - C - OH ---> HO - C - C - C - OH
ll
C - R
Then cyclisation(intra-esterification) follows and the product is resulted.
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http://www.organic-chemistry.org/namedreactions/knoevenagel-condensation.shtm
Malonic acid easily decarboxylate, use its ester
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I thought Knoevenagel didn't work too well with 3° amines. You only need a catalytic amount anyway.
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It is not Knoevenagel condensation, it is just simply an aldol condensation.
that is a Knoevenagel condensation. And as for post one, what do alcohols and acids do in acidic media?