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Chemistry Forums for Students => High School Chemistry Forum => Topic started by: hawkslax7 on November 06, 2007, 10:03:45 PM

Title: Lewis Structure of IF5
Post by: hawkslax7 on November 06, 2007, 10:03:45 PM

I'm having trouble drawing the lewis stucture of IF5. I was wondering if anyone could help.

Thanks.

Title: Re: Lewis Structure of IF5
Post by: agrobert on November 06, 2007, 10:31:23 PM

For 6 X^- (with 7e^- each) -->

7e^-(6) = 42e^- - 6e^- (5 F with three sets of lone pairs each) =

12e^- - 2e^-(5 I-F bonds sharing electrons) =

2e^- which accounts for lone pair on I

So

7(6) total electrons = 42

42-30 (non-bonding on F) = 12

12-10 (bonding I-F) = 2

2 (lone pair on I)

Now try drawing the Lewis structure if you understand this.

Understand that some halogens and other elements can have expanded octets and higher oxidation states.

http://en.wikipedia.org/wiki/Iodine_pentafluoride

Title: Re: Lewis Structure of IF5
Post by: AWK on November 07, 2007, 01:05:52 AM

http://en.wikipedia.org/wiki/PF5

Title: Re: Lewis Structure of IF5
Post by: agrobert on November 07, 2007, 01:25:24 AM

Quote from: AWK on November 07, 2007, 01:05:52 AM

http://en.wikipedia.org/wiki/PF5

This is not the same

Title: Re: Lewis Structure of IF5
Post by: AWK on November 07, 2007, 05:12:06 AM

That's right, but we do not give here an exact solution, in this case for comparison with you good answer.
http://en.wikipedia.org/wiki/VSEPR
http://www.albion.edu/chemistry/LBL/S07%20Molecular%20Shape.ppt