Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: starry on February 21, 2008, 05:11:40 PM
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Could someone explain to me how to go about this problem? Thanks:
The half-life for radioactive decay (a first-order process) of plutonium-239 is 24,000 years.
How many years would it take for one mole of this radioactive material to decay so that just one atom remains?
t = __?__ yrs
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Humph. Cute question they've given you. Ok, for starters, you should ask yourself what the definition of half-life is, that's a pretty easy one. You're given half-life, in years. You're told you have a mole of Pu, and the answer is in atoms(well, 1 atom,) so you'll have to convert those to units.
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Start here:
http://www.colorado.edu/physics/2000/isotopes/radioactive_decay3.html
http://www.chem.arizona.edu/~salzmanr/480a/480ants/kinintro/kinintro.html
http://www.chm.davidson.edu/ChemistryApplets/kinetics/IntegratedRateLaws.html
http://www.cartage.org.lb/en/themes/sciences/chemistry/NuclearChemistry/NuclChemIndex/Kineticsradioactive/Kineticsradioactive.htm
http://en.wikipedia.org/wiki/Half-life
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Aye, I think I converted the units. since its mass is 239, that's one mole of it. One atom 6.02*10^23?
Not sure where to go from that though.
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Aye, I think I converted the units. since its mass is 239, that's one mole of it. One atom 6.02*10^23?
Not sure where to go from that though.
OK, 6.022 x 1023 atoms is one mole. You won't be needing atomic mass this time, because the problem never mentions mass. ;) Keep that in mind for the next problem 'tho.
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Okay, well.. got that part. XD
What are the next steps I need to take?
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Dear Starry;
If you got that, and also the Definition of the “Half-Lifetime”:
How many Moles of 239Pu will be remaining after the first “Half-Lifetime”?
And how many Moles will be left after the second “Half-Lifetime”?
And after the fourth, - and so on?
Do you realise that it will end in a so called “Geometric Series”?
Will this hint bring you a Step ahead, or do you know how this Kinetic is calculated?
Good Luck!
ARGOS++