Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: mollyp on September 01, 2008, 06:12:18 PM
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Hi,
I am having trouble figuring this:
What is the total ion concentration of a 0.43 M solution of potassium oxalate?
K2C2O4 * H20
Can you get me started?
Thanks!
MOlly
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How does it dissociate?
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2K+ 2C4+ 5O2- 2H+
Right?
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2K+ 2C4+ 5O2- 2H+
Right?
No, polyatomic ions do not decompose into their elements in solution (and neither does water)
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Ok. I am probably overthinking this, but I am totally clueless as to what I need to do to find this.
Borek, asked me "How does it dissociate?" Which to me means how does it break into ions. But, if I have K2C2O4 + H20 do I have one ion + one water molecule? I just don't see how to calculate this.
Thank you!
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"How does it dissociate?" Which to me means how does it break into ions.
Yes, good
But, if I have K2C2O4 + H20 do I have one ion + one water molecule?
Not just one ion but yes there is one water molecule
An example:
Li2SO4 dissociates into Li+ (but how many Li+ do you get?) and SO42- . Notice what happens to the polyatomic ion. How many ions are there now?
Now what would happen with potassium oxalate?
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OHHHHHHH! Yup, I totally did not even think about that oxalate being its own entity...
Ok, so I will have K+ & C2O42- So I will have 3 total ions, 2 K+ & 1 C2O42-
SO,
.43 M x 3mols = 1.3 mols/L
Did I get it?
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Yes :)
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Thank you SO much! I am so glad I found this site! I have actually been able to help a few of the people in the High School Chem forum with some of their problems. Give some, take some! Fantastic!! ;D