Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: slu1986 on October 09, 2008, 05:01:39 PM
-
I am trying to figure out how to calculate ln k using the arrhenius equation b/c I have to graph ln k vs. 1/T
The temperature is 24.7 C and in Kelvin = 298 K
These are the values that that my graph gave for a first order reaction
m(slope) = -0.0008313
b (Y intercept) = -0.8794
Arrhenius Equation: ln k = -Ea/R (1/T) + ln (A)<----- this is the y = mx + b form of the equation, however I am having trouble understanding how to solve it.
ln k = - 0.0008313/8.314 J/mol K (1/298 K) + ln (-0.8794) <----this is how I set up the numbers but I dont think its right...Could someone please help me understand how to do this so I can solve for my three rate constants and make my graph of ln k vs. 1/T
-
hi.
These are the values that that my graph gave for a first order reaction
m(slope) = -0.0008313
b (Y intercept) = -0.8794
Graph of ln K against 1/T? if it is, then you subsitute your value in wrongly. ln A should be = -0.8794. same for the gradient.
-
that's what i put for ln A. Can someone help me understand how to get the ln k from my data using the arrhenius equation?
-
that's what i put for ln A.
But in your first post, you put c = ln (-0.8794), where it should be c= ln A = -0.8794, no?
-
I am so confused about what you are saying.
-
hi,
m(slope) = -0.0008313
b (Y intercept) = -0.8794
Arrhenius Equation: ln k = -Ea/R (1/T) + ln (A)<----- this is the y = mx + b form of the equation, however I am having trouble understanding how to solve it.
ln k = - 0.0008313/8.314 J/mol K (1/298 K) + ln (-0.8794) <----this is how I set up the numbers but I dont think its right...
What is your y-intecept? It's defined by you as b right, and in actual b = ln A, where A is the pre-exponential factor.
So when you obtain the y-intecept from the graph is -0.8794, right? and should be equivalent to b = ln A = -0.8794
But look at the math which i bolded it, instead of substiuting the whole y-intecept as -0.8794, you actual ln (y-intecept) which is wrong ye?
-
In an Arrhenius plot, the slope is -Ea/R and the intercept is lnA. If you have a slope and y intercept, you are done! Just do these calculations. However, your intercept looks a bit screwy. The frequency factor is usually a pretty large number, so your y intercept looks to be in error.