Chemical Forums
Chemistry Forums for Students => Analytical Chemistry Forum => Topic started by: Chaste on October 27, 2010, 10:43:11 AM
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Equilibria involved :
FeG+ + G- ::equil:: FeG2 K2 = 3.2 x 103
G- + H2O ::equil:: HG + OH- Kb = 6.0 x 10-5
G- is the amino acid glycine.
Suppose that 0.050 mole of FeG2 is dissolved in 1 litre of water.
Qns: Using activity coefficient, find FeG+ if the pH is fixed at 8.5 and the ionic strength is 0.10M. For FeG+, use gamma = 0.79. and for G- use gamma = 0.782
My attempt at the question:
MBE 1 = 0.05 = [FeG+] + [FeG2]
MBE 2 = [FeG+] = [HG] + [G-]
the ionic strength being 0.1,
0.1 = 0.5 x [FeG+] + [G-] + [H3O+] + [OH-] ----- 1
and I'm stuck. I suppose I need to solve simultaneous equations. how do I make use of the pH and activity coefficients to resolve this question?
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Can use debye-hukal law to relate the concentration and ionic strength.
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hi there, thanks for the contribution. The question has been there for a while and it has been solved.