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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Mal1ce on December 12, 2010, 06:40:50 PM

Title: Oxidation Number
Post by: Mal1ce on December 12, 2010, 06:40:50 PM
IO3- + I- + Cl-  :rarrow: ICl2-

So I am trying to balance this equation but I don't know how to assign the oxidation number for ICl2-. Is the Cl2 0 and I -1?
Title: Re: Oxidation Number
Post by: Hybrid on December 13, 2010, 12:58:11 AM
no in this case I +1 and Cl -1 electronegativity .

that is called andrewss method for assay of iodide

as you write your equation balance will be like that

IO3- + I- + Cl-  _______  ICl2-

(I+5 O-6) -   +2 I-  + 6Cl- ____+  6H+ _________ 3(I+1 Cl-2) -  + 3H2O

but actually don't add Cl- to formed ICl = ICl2-

IO3- + 2I- + 6HCl ---> 3ICl + 3Cl- + 3H2O


Title: Re: Oxidation Number
Post by: Mal1ce on December 13, 2010, 04:03:47 PM
Thank you.