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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: bravoghost on March 19, 2011, 08:36:20 PM

Title: Ionization Energy of Carbon
Post by: bravoghost on March 19, 2011, 08:36:20 PM
I found that it takes 11.26 eV to liberate the first electron off a neutral carbon atom. I needed to calculate the wavelength, and my final answer was around 15 nm. I watched someone do the same problem online, and they got roughly 150 nm. Who was right?
Title: Re: Ionization Energy of Carbon
Post by: opti384 on March 19, 2011, 10:17:21 PM
Can you show your process?
Title: Re: Ionization Energy of Carbon
Post by: bravoghost on March 27, 2011, 08:14:51 PM
So I did the problem without such liberal rounding, and it came out to about 1.11*10^-7.

11.26 eV = 1.6*10^-19 C

Thus, 11.26 x 1.6*10^-19 = 1.8*10^-18 C (the energy of the ionization)

E=hf
1.8*10^-18 = 6.63*10^-34 x f
f = 2.71*10^15

v=λf
3*10^8 = λ x 2.71*10^15
λ = 1.11*10^-7 m

but that isn't 110 nm, right? If we put that number in nanometers, it'd be .011 nm, right??
Title: Re: Ionization Energy of Carbon
Post by: rabolisk on March 27, 2011, 08:35:22 PM
So I did the problem without such liberal rounding, and it came out to about 1.11*10^-7.

11.26 eV = 1.6*10^-19 C

This makes no sense.

Thus, 11.26 x 1.6*10^-19 = 1.8*10^-18 C (the energy of the ionization)

Neither does this.

E=hf
1.8*10^-18 = 6.63*10^-34 x f
f = 2.71*10^15

v=λf
3*10^8 = λ x 2.71*10^15
λ = 1.11*10^-7 m

Nevertheless, this is correct.

1 nanometer is 10-9 meter.