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Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: skp524 on January 20, 2012, 02:15:14 PM

Title: Elimination reaction
Post by: skp524 on January 20, 2012, 02:15:14 PM

Can anyone please explain why this product is formed instead of any other possible product(s)? http://www.sendspace.com/file/6ze3yf (http://www.sendspace.com/file/6ze3yf) Is that the amine will first attack the most electrophilic carbon , the one "separates" 2 bromine atoms. Alkylated amine is then formed  and it will in turn form a double bond on the previosuly mentioned carbon atom and the one near to this atom and to carbonyl group , i.e. C=C on upper carbon and middle carbon atoms. This is because the delocalization of pi electrons can increase the stability of the product .

Title: Re: Elimination reaction
Post by: Honclbrif on January 20, 2012, 03:29:29 PM

Can you link directly to an image? I'm personally a little leery about downloading files from strange websites.

Title: Re: Elimination reaction
Post by: orgopete on January 20, 2012, 05:56:55 PM

I agree with Honclbrif, please attach the image to your post. Click on Additional Options below the edit box, then attach the file. A jpg file will be viewable directly in the forum.

Title: Re: Elimination reaction
Post by: skp524 on January 21, 2012, 05:34:46 AM

The organic reaction is attached here

Title: Re: Elimination reaction
Post by: discodermolide on January 21, 2012, 11:30:49 AM

Quote from: skp524 on January 21, 2012, 05:34:46 AM

The organic reaction is attached here

Look for the two most acidic protons in the SM and you will get your answer.