Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: Kommandante on December 09, 2013, 04:44:38 PM
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Hi there,
I have been given the formula for Iron(III) Oxide (Fe2O3) and have been asked to calculate how many moles are present in 24.6g of the compound whilst working out how many moles of Fe are present in this amount.
I have calculated the mole of Fe2O3 at 0.154 mol,
M= (Fe2O3), M= 2(55.8 ) + 3(16.0)
m = 24.6, M = 159.6, n = ? so, n = m/M, 24.6/159.6 = 0.154mol
I cannot for the life of me grasp how to find out the mol of Fe in 24.6g this compound.
Do I divide the mol of Iron by the weight of the compound? Convert it to a percentage?
Any help would be greatly appreciated
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its more easier. You know the moles of the compound then you know also the moles of each atom. Its given to the formula. Example 1 mol NaCl contain also 1 mol Na+ and 1 mol Cl-. So how much is it for the iron oxide.
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Since the compound is 0.154 mol, does that mean there are 2(0.154)mol Fe?
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Exactly. correct.
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Thanks for your help,
Greatly appreciated!