Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: xJax on July 13, 2017, 08:51:36 PM
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Hi guys, can someone provide me a worked solution to this question. I've not learnt 'percentage solution' before:
"a 50kg patient requires 10mcg/kg/minute for 2 hours. this is to be delivered from a 0.1% solution, how much solution will they need in mL?".
Thank-you! :)
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Hi guys, can someone provide me a worked solution to this question. I've not learnt 'percentage solution' before:
High there, xJax:, I'd like to welcome you to the chemical forums. But I'd like to remind you to read our Forum Rules{click} (http://www.chemicalforums.com/index.php?topic=65859.0), you agreed to them when you signed up, and they apply to everyone: new students, seasoned professionals, and people who just need to know right now. We like to see some effort from you. Let's work together:
"a 50kg patient requires 10mcg/kg/minute for 2 hours. this is to be delivered from a 0.1% solution, how much solution will they need in mL?".
Thank-you! :)
The fractional percentage seems to be throwing you. That's OK, that's the toughest part of this problem. But work out the first bit for us -- 50 kg needs 10mcg (which means what? This is jargon here, you must look up what it means, or just stick with the jargon and report it that way)/kg/min per 2hrs. How much is that?
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Hi guys, can someone provide me a worked solution to this question. I've not learnt 'percentage solution' before:
"a 50kg patient requires 10mcg/kg/minute for 2 hours. this is to be delivered from a 0.1% solution, how much solution will they need in mL?".
Thank-you! :)
Go like this
10mcg/Kg = x mcg/ 50 Kg
Then convert it from one minute to 2 Hours ( 2 hours = 120 minutes)
0.1 % means 0.1mcg per 100 mL
use it to get the answer.
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I tried it and got 10mL as the answer. Is this correct?
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Can you show me the calculations?