Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: plswhy on May 18, 2018, 02:22:22 AM
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a) If 65 mL of 1.00 M HCl is mixed with 35 mL of 1.00M NaOH, how many moles of each ion are present BEFORE the reaction?
So I understand that HCl + NaOH --> NaCl + H2O and that HCl = 0.065 mol and NaOH= 0.35 mol. I'm just a bit stuck as to how to calculate the individual ions. Please *delete me* Thank you!
Na+
Cl-
H30+
OH-
b) Which reactant is the limiting reagent
c) What are the final concentrations of all the ions present?
d) What is the pH of the final solution.
Thanks so much!
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HCl = 0.065 mol and NaOH= 0.35 mol
Check your math, only one of these is OK.
If 0.065 moles of HCl dissociates, how many moles of H+ are produced?