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 1 
 on: Today at 12:11:51 PM 
Started by Clifftub - Last post by Clifftub
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 2 
 on: Today at 11:50:51 AM 
Started by Jotaro - Last post by Jotaro
Dear all,

I am new to this forum and really glad this forum exists!
I am working with radiochemistry, with no chemistry background. Not the best introduction, but I have to be honest. Still, I manage to do my job.

I have a question regarding the Polonium instant deposition (plating) on Cu discs (also applicable on Ni and Ag discs).
The procedure I work with (after liquid-liquid extraction with TBP and Xylene) I dry the 8M HNO3 fraction that contains the Po. Change the media to about 2M HCL, my question is why is HCL used? I understand that HNO3 would eat away Cu and other metal discs, but does the HCL help to plate the Po on the Cu disc?

Thank you for your time


 3 
 on: Today at 10:35:19 AM 
Started by Nerdos - Last post by Babcock_Hall
How do you explain the odd number of hydrogens in C14H27O?

 4 
 on: Today at 09:32:13 AM 
Started by Egyptian - Last post by Babcock_Hall
@OP, It is a forum rule that you must show us your attempt at answering a question before we can help you.  Have you looked in a bioinorganic textbook, for example?

 5 
 on: Today at 09:09:41 AM 
Started by HowDoIScience - Last post by chenbeier
Yes you are right Sulphur has the highest oxidation number.

 6 
 on: Today at 08:54:01 AM 
Started by owlpower - Last post by spirochete
They should both be correct, but it would be good to understand here that you can't really observe syn addition in that product, because only one chirality center is formed. So it's a little weird to draw the H as a wedge. Syn and anti addition would give the same product in that molecule, due to free single bond rotation.

 7 
 on: Today at 08:50:16 AM 
Started by mana - Last post by spirochete
It seems to be that benzyne mechanism happens if the group is only electron withdrawing by induction. This feels strange to me because CF3 is one of the strongest deactivators in EAS, which suggests it is similar withdrawing strength to nitro. But in the case of CF3/NaNH2, the benzyne mechanism still happens.

I do wonder why CF3 is so strongly withdrawing in EAS, but appears to be less withdrawing for NAS.

 8 
 on: Today at 08:32:52 AM 
Started by HowDoIScience - Last post by HowDoIScience
So is that literally the only way to work out the oxidation numbers,  there is no other way?

Yes.

Quote
Also is MgSO3 the right answer?

Why don't you try to apply the rules and calculate? That's basically how you do the science.

I have, but I'm unsure I'm correct,  that is the only reason I'm asking. I've done it for each of the compounds, and I think it's MgSO3 but I'm not one hundred percent positive.

 9 
 on: Today at 08:05:47 AM 
Started by Nerdos - Last post by Nerdos
I'm hesitating between C14H28O and C14H27O.

 10 
 on: Today at 08:01:10 AM 
Started by Nerdos - Last post by chenbeier
Tell us your ideas first.

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