Pre-1982
(8.96g/ml * x ) + (7.14g/ml * y) = 8.1
Where x and y are the percent. I.E. 88% is 0.88. So 100 * 0.88 gives you 88, which is 88 percent.
When you have just two percents of one thing, they both must add up to 1 , so you can replace y with (1-x)
So now you have
(8.96g/ml * x) + (7.14g/ml * 1-x ) = 8.1
Solve for x (algebra and quadratic). You then get the percent composition for x (which how I have the numbers arranged, Copper). Zinc percent composition is then just 1-x.
In this case so you can know you are getting the math correct, I will tell you that by those numbers pre-82 Cu was 0.5274 (* 100) = 52.74 %, and so Zn is 47.26%.
Repeat for post-1982. This is just basic algebra practice.