[HolyCow]

in the lab i mesured the themperature changes of the following reactions:
HCl + NaOH -> NaCl + H2O
CH3COOH + NaOH -> CH3COONa + H2O

I was able to calculate the reaction potentials(respectively -35.0kJ/mol and -1.6kJ/mol)
but than i was asked to calculate the ionisation-potentials of CH3COOH
how must i do that?

i did it like this: H(ionisation-potential) = Hreaction1 + Hreaction2
                                                        = -35.0 + (-1.6) = -36.6 kJ/mol

is this correct or doesnt this make any sence, if so, how should i do that?

thanks very much

[Demotivator]

not correct.
you must first reverse an equation, then add and cancel terms (ions) to yield the net ionization equation:

CH3COOH  --> CH3COO-  +  H+

And add the potentials taking into account the effect of reversal,

[HolyCow]

-(HCl + NaOH -> NaCl + H2O)
CH3COOH + NaOH -> CH3COONa + H2O
CH3COOH + NaCl -> HCl + CH3COONa
CH3COOH + Cl-  ->  HCl + CH3COO-

-(-35kJ/mol) - 1.6kJ/mol = 33.4 kJ/mol

like this?

[Demotivator]

yes