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Topic: Calculation  (Read 8099 times)

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Offline croatian

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Calculation
« on: May 21, 2007, 08:05:19 AM »
What is the maximum number of grams of PH3 that can be formed when 6.2 grams of phosphorus reacts with 4.0 grams of hydrogen to form PH3?

P4 + 6H2 ----> 4PH3

6.2 g * (1 mol / 31 g) = 0.2 mol of P (LIMITING REACTANT)

4.0 g * (1 mol / 1 g) = 4 mol of H2

So...

6.2 g * (1 mol / 124 g) * (4 mol / 1 mol) * (34 g / 1 mol) = 6.8 g of PH3


Is that correct?

Offline Borek

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Re: Calculation
« Reply #1 on: May 21, 2007, 08:17:05 AM »
OK
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Offline AWK

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Re: Calculation
« Reply #2 on: May 21, 2007, 08:28:39 AM »
4 grams of hydrogen is equal to 2 moles of H2 but a final result is correct
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