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Author Topic: Lewis Structure of IF5  (Read 40969 times)

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hawkslax7

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Lewis Structure of IF5
« on: November 06, 2007, 04:03:45 PM »

I'm having trouble drawing the lewis stucture of IF5. I was wondering if anyone could help.

Thanks.
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agrobert

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Re: Lewis Structure of IF5
« Reply #1 on: November 06, 2007, 04:31:23 PM »

For 6 X- (with 7e- each) -->

7e-(6) = 42e- - 6e- (5 F with three sets of lone pairs each) =

12e- - 2e-(5 I-F bonds sharing electrons) =

2e- which accounts for lone pair on I

So

7(6) total electrons = 42

42-30 (non-bonding on F) = 12

12-10 (bonding I-F) = 2

2 (lone pair on I)

Now try drawing the Lewis structure if you understand this.

Understand that some halogens and other elements can have expanded octets and higher oxidation states.

http://en.wikipedia.org/wiki/Iodine_pentafluoride
« Last Edit: November 06, 2007, 08:33:55 PM by agrobert »
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AWK

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Re: Lewis Structure of IF5
« Reply #2 on: November 06, 2007, 07:05:52 PM »

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agrobert

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Re: Lewis Structure of IF5
« Reply #3 on: November 06, 2007, 07:25:24 PM »

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AWK

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Re: Lewis Structure of IF5
« Reply #4 on: November 06, 2007, 11:12:06 PM »

That's right, but we do not give here an exact solution, in this case for comparison with you good answer.
http://en.wikipedia.org/wiki/VSEPR
http://www.albion.edu/chemistry/LBL/S07%20Molecular%20Shape.ppt
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