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### AuthorTopic: coeff * wavelength associated w/ electron transition of H 4 Li2+ ion (resolved)  (Read 2918 times) !function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0];if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src="https://platform.twitter.com/widgets.js";fjs.parentNode.insertBefore(js,fjs);}}(document,"script","twitter-wjs"); (function() {var po = document.createElement("script"); po.type = "text/javascript"; po.async = true;po.src = "https://apis.google.com/js/plusone.js";var s = document.getElementsByTagName("script")[0]; s.parentNode.insertBefore(po, s);})();

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#### kyasarin

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##### coeff * wavelength associated w/ electron transition of H 4 Li2+ ion (resolved)
« on: December 08, 2007, 09:30:50 PM »

The wavelength of light associated with the n = 2 to n = 1 electron transition in the H spectrum is 1.216 x 10-7 m. By what coefficient should this wavelength be multiplied to obtain the wavelength associated with the same electron transition in the Li2+ ion?
a)1/9
b)1/7
c)1/4
d)1/3
e)1

I have no idea because we only covered H and the formula "∆E = 2.178 X 10-18 J[1/n2i – 1/n2f]" I have also had trouble with questions concerning this equations (see post titled "minimum wavelength to excite an electron".
So to sum it all up i am at total loss, except that I'm almost sure it is not e.
« Last Edit: December 10, 2007, 01:39:40 AM by kyasarin »
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#### kyasarin

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##### Re: coefficient * wavelength associated with electron transition of H 4 Li2+ ion
« Reply #1 on: December 10, 2007, 01:38:44 AM »

I have no idea because we only covered H and the formula "∆E = 2.178 X 10-18 J[1/n2i – 1/n2f]" ... So to sum it all up i am at total loss, except that I'm almost sure it is not e.

I just realized that Li starts w/ 3 electrons & the Li2+ ion has lost 2 electrons so it now only has 1 like H. So I am hypothesizing that the answer is e) 1. (which is the only one I thought is wasn't. Wow, can you tell i was doing this really late at night?
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