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Author Topic: Oxidation number of Sulphur in Thiosulphate ion.  (Read 13879 times)

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purple_glitter

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Oxidation number of Sulphur in Thiosulphate ion.
« on: January 31, 2008, 08:26:38 PM »

The oxidation number of sulphur in sodium thiosulphate is designated as (VI). Why is the oxidation number of sulphur +6 and not +2? Can it be proven?
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AWK

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Re: Oxidation number of Sulphur in Thiosulphate ion.
« Reply #1 on: January 31, 2008, 09:41:29 PM »

According to oxidation rules, the oxidation number of sulfur in thiosulfate is +4 an 0 - and mean value +2 for both sulfur atoms
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Borek

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Re: Oxidation number of Sulphur in Thiosulphate ion.
« Reply #2 on: January 31, 2008, 09:58:08 PM »

Why not +6 and -2 by analogy to SO42- with one oxygen replaced by S?

Oxidation numbers are just an accounting device used for equation balancing, they don't describe any real property of the matter. So this question has no meaningful answer.
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AWK

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Re: Oxidation number of Sulphur in Thiosulphate ion.
« Reply #3 on: February 01, 2008, 12:23:24 AM »

Why not +6 and -2 by analogy to SO42- with one oxygen replaced by S?

We neglect all bond between atoms of the same kind as in elements. This a rule, and only rule. But I often use artificial oxidation numbers for solving, so called, difficult redox reaction.

I agree absolutely with a second part of Borek statement.
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Borek

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Re: Oxidation number of Sulphur in Thiosulphate ion.
« Reply #4 on: February 01, 2008, 01:34:01 AM »

Why not +6 and -2 by analogy to SO42- with one oxygen replaced by S?

We neglect all bond between atoms of the same kind as in elements. This a rule, and only rule. But I often use artificial oxidation numbers for solving, so called, difficult redox reaction.

It was rather a rhetorical question - I know the rule you are referring to, it just doesn't matter whether we use it (which ends with +4/0) or treat thiosulfate as a 'higher analogue' of sulfate (which ends in +6/-2) - in both cases final result of the balancing will be the same. Which just shows that these rules are arbitrary.
« Last Edit: February 01, 2008, 03:36:27 AM by Borek »
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