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Offline Spectrum

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Need help balancing
« on: February 24, 2008, 03:41:01 PM »

Al + 3KOH + H2O + 3C2H2O4.H2O --> K3[Al(C2O4)3].H2O + 4.5H2 + 5H2O


Hmmm, that's what I get when I balance it.
« Last Edit: February 24, 2008, 03:55:19 PM by Spectrum »

Offline Borek

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Re: Need help balancing
« Reply #1 on: February 24, 2008, 03:45:29 PM »
What gas is produced when dissolving Al in strong base? Move water to products as well - although what will really happen depends on the crystallic form of your product.
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Offline Spectrum

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Re: Need help balancing
« Reply #2 on: February 24, 2008, 03:55:33 PM »
Al + 3KOH + H2O + 3C2H2O4.H2O --> K3[Al(C2O4)3].H2O + 4.5H2 + 5H2O


Hmmm, that's what I get when I balance it.

Offline Borek

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Re: Need help balancing
« Reply #3 on: February 24, 2008, 04:38:37 PM »
4.5H2?

Water on both sides? Some coefficients are OK, but in general equation is still not balanced.
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Offline Spectrum

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Re: Need help balancing
« Reply #4 on: February 26, 2008, 01:28:10 PM »
After working on this a bit today and yesterday. I have come up with K3[Al(C2O4)3] as my product that I made.

Now, after I made this product. I took some of it and dissovled it in dilute sulphuric acid (50cm3) and then 100cm3 of water. I then titrated it with potassium permanganate (0.01979mol l-1)

The only problem I have now is that I don't understand how this helps me to find the %ethanedioate in my product and then elps me estimate a value for x in the formula for the complex, K3[Al(C2O4)3] xH2O

Offline Borek

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Re: Need help balancing
« Reply #5 on: February 26, 2008, 01:32:17 PM »
Titration should give information about number of moles - as you have (hopefully) weigthed your sample before titration, you know mass and number of moles - that gives molar mass. And molar mass is a simple function of x.
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Offline Spectrum

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Re: Need help balancing
« Reply #6 on: February 26, 2008, 01:49:39 PM »
So if I had 0.1504g of product and that took around 21cm3 to titrate.

So number of moles = 0.01979 x 21cm3 = 0.0004moles

That would mean a molar mass = 0.1504/0.0004 = 361.895.

So if the Mr of my product is 411.3348. I then subtract them to get 50. then if i divide this by the mr of water, which is roughly 18, i get 2.78, which is closer to 3 i guess, so the number for X, is 3?


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Re: Need help balancing
« Reply #7 on: February 26, 2008, 03:00:28 PM »
Reasoning seems to be correct.

But then, without knowing your numbers, experimental procedure, blah blah and blah blah, you can be wrong. I can't tell, I just don't know enough.
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