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Topic: Partition coefficent help  (Read 5659 times)

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Offline mass

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Partition coefficent help
« on: February 27, 2008, 05:07:51 AM »
In an experiment a 0.02M solution of benzoic acid in 0.02M of HCL is provided (solution X).
The benzoic acid in X is unionized - explain why.

I don't understand why the benzoic acid would be unionized, is it just simply because it isn't protonated?

Offline Borek

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Re: Partition coefficent help
« Reply #1 on: February 27, 2008, 05:19:22 AM »
unionized = not dissociated = protonated
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Offline mass

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Re: Partition coefficent help
« Reply #2 on: February 27, 2008, 07:10:04 AM »
unionized = not dissociated = protonated

what is the benzoic acid protonated by though?

Offline Arkcon

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Re: Partition coefficent help
« Reply #3 on: February 27, 2008, 07:20:08 AM »
unionized = not dissociated = protonated

what is the benzoic acid protonated by though?

Simple.  Bases are protonated by acids.  Very strong acids protonate water, for example, which can function as an acid or a base.  Compared to HCl, benzoic acid is a base.  If there was no HCl in the solution, benzoic acid would protonate the water, and would be an ion, and would dissolve.
Hey, I'm not judging.  I just like to shoot straight.  I'm a man of science.

Offline Borek

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Re: Partition coefficent help
« Reply #4 on: February 27, 2008, 07:38:42 AM »
Note: it is not benzoic ACID that gets protonated. It is benzoate anion that is base, that is protonated.

HBenzoate <-> H+ + Benzoate-

This is weak acid, it dissociates only slightly. When you add excess H+, equilbrium moves to the left.
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Offline mass

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Re: Partition coefficent help
« Reply #5 on: February 28, 2008, 05:49:08 PM »
Ah Yes I get it, thank you.

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