[ARGOS++]

Dear Frederick95;

I got quite close the same, if , if I divide YOUR result by 1000!, but for how many Moles Acetone, and that’s how many Grams?

Good Luck!
                    ARGOS⁺⁺

[Frederick95]

I got 0.0015 mol C3H6O(acetone) as an answer. But what to do with this?

[ARGOS++]

Dear Frederick95;

You got Q, but you need Q per Mole, also Q / Mole!
(Use at least 2 figures more!! You can round your end result, - Not before!)


Good Luck!
                    ARGOS⁺⁺

[Frederick95]

AHA!! SO....

2317.5 / 0.0015 mol C3H6O

= 1545000 J?

[ARGOS++]

Dear Frederick95;

NO!,  –   I told you:  Use at least 2 figures more!!

That will give you:  H =  - 1462.6  kJoules / mole for Acetone.

Good Luck!
                    ARGOS⁺⁺

[Frederick95]

1462.6  kJoules?

But why not 2317.5 kJ?

[ARGOS++]

Dear Frederick95;

Why should it?

Good Luck!
                    ARGOS⁺⁺

[Frederick95]

Because 2317.5 kJ is the value we got for q

1462.5 does not = q

[ARGOS++]

Dear Frederick95;

Please read correct:   H =  - 1462.6  kJoules / mole for Acetone.
(That's a little more precise = 2.320 kJoules / 0.001586 moles.)

Good Luck!
                    ARGOS⁺⁺

[Frederick95]

OHHHH!


So Enthalpy = 2.320 kJoules / 0.001586 moles

Therefore Enthalpy(H) is 1462 kJ/mol?

[ARGOS++]

Dear Frederick95;

Don’t miss the Sign, as you told in your Question!

      H = - Q = - 455 J = -0.455 kJ
     Number of moles (n) = (given mass (g))/(gram-formula mass)

Good Luck!
                    ARGOS⁺⁺

[Frederick95]

Enthalpy -1462 kJ/mol (because it is exothermic)?

[ARGOS++]

Dear Frederick95;

Precisely!

Good Luck!
                    ARGOS⁺⁺

[Frederick95]

THANK YOU ARGO YOU ARE THE BEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

I will not forget you!!!:)

[ARGOS++]

Dear Frederick95;

You’re welcome!   ─   Soon (but not toooo soon!) again.


Good Luck!
                    ARGOS⁺⁺