[oceanmd]

What is the freezing point of a solution containing 85 g of NaBr in 0.5 kg of water?

My solution: 85 g NaBr = 85 / 102.89 = 0.826 mol NaBr
molality = 0.826 / 0.5 kg =1.652 mol
The freezing point depression is 1.86 x 1.652 = 3.073 degrees C
The freezing point od a solution is 0-3.073 = -3.073 degrees C

Is thsi correct? Thank you

[Borek]

You were already asked before to not posts lists of your question, but - if you must ask for result confirmation - to combine them into one post. You have been warned, but you still do the same. Also take a look at scooby snack balance - -16 against +1. We have nothing against helping you, but your posts are being seen as abuse of our hospitality.

I have no choice. Temporary ban.