[AWK]

3.  The solubility product constant for Strontium Chromate is 3.6x10^-5.  What is the solubility in g/100mL

MW=204
Ksp=[Sr][CrO4]=x^2
x^2=3.6x10^-5
x=6x10^-3=M
g/L=(6x10^-3)(204)=1.224)(.1L)/(100mL)= 1.224x10^-4 g/100mL

should be 0.12 g !

[Gravemind]

I have a strong feeling g/L=(6x10^-3)(204)=1.224 is correct, which would make my dimensional analysis wrong.

g/L to g/mL       (g/L)(L/mL)=g/mL

(1.224g/L)(.1L/100mL)=1.22x10^-3

I must be missing something, because everything looks right

[Borek]

(1.224g/L)(.1L/100mL)=1.22x10^-3

This is g/mL, you are asked for something else.

[AWK]

g/L is OK
100 mL comtains 10 % of this quantities