[Schrödinger]

Is it possible for me to hide my text?

Like... the heading says 'click to reveal content (or something else)' and when you click on it the hidden text appears...like in the mathlinks forum?

[Mitch]

The internet use to use Rot 13 for things like that.

Srry serr gb hfr vg urer ng purzvpnysbehzf.pbz

[Schrödinger]

Gunax lbh, ohg vfag guvf whfg qrpbqvat ?

[Mitch]

Lrnu, ohg va n frafr vg npgf yvxr n fcbvyre gnt. Juvpu frrzf gb or jung lbh jrer trggvat ng.
</rot 13>

[Schrödinger]

Ok, I'm getting tired of having to refer to Wikipedia every time to decode this. It's consuming a lot of time. What does </rot 13> do? I can't seem to use it in my posts

[Mitch]

It doesn't mean anything, I just put it so you would know what I was doing.

More importantly, you have been doing this by hand!?? Just use this: http://www.rot13.com/

[Schrödinger]

Thanks for the link Mitch. I'm starting to like this now.
Oh... and please don't mistake my tone in my last post... I was getting totally stressed out doing it by hand

[Matias Ekstrand]

I'm not exactly sure how you integrated LaTeX into the forum. You didn't use the Mimetex SMF-mod for it due to the different tags and lack of latex button in the text editor menu, so I suppose you made something custom.

I tend to use LaTeX a lot, and the use of a button in the text editor menu to get the tags makes it much simpler to integrate into forum posts.

My suggestion:
- It might be easier for you to use the Mimetex SMF-mod (doesn't cause problems at forum updates compared to custom code).
- If not, could you please create a BBCode button for the LaTeX tags? You could probably use this mod for creating it.

[haz658]

Practicing.

Code: [Select]

$$ y = mx +b /$$

[haz658]

Practicing.

$$ y = mx + b /$$

[haz658]

Determining whether what I am about to post will turn out properly. My apologies.



$$\begin {eqnarray} ln \left (\frac{W_{max}} {W} \right) & = & \sum_{n} a_n \alpha_n \mathbf {ln a_n} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n})  \nonumber  \\  & = & \sum_{n} a_n \alpha_n \mathbf {(ln a_0 - \beta \varepsilon_n)} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n})  \nonumber \end{eqnarray} /$$

[haz658]

$$\begin {equarray*} ln \left (\frac{W_{max}} {W} \right) & = & \sum_{n} a_n \alpha_n \mathbf {ln a_n} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \\ & = & \sum_{n} a_n \alpha_n \mathbf {(ln a_0 - \beta \varepsilon_n)} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \end{equarray*} /$$

[haz658]

$$\begin {eqnarray*} ln \left (\frac{W_{max}} {W} \right) & = & \sum_{n} a_n \alpha_n \mathbf {ln a_n} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \\ & = & \sum_{n} a_n \alpha_n \mathbf {(ln a_0 - \beta \varepsilon_n)} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \end{eqnarray*} /$$



$$\begin {eqnarray} ln \left (\frac{W_{max}} {W} \right) & = & \sum_{n} a_n \alpha_n \mathbf {ln a_n} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \\ & = & \sum_{n} a_n \alpha_n \mathbf {(ln a_0 - \beta \varepsilon_n)} + \sum_{n} \frac {a_n} {2} (\alpha^{2}_{n}) \end{eqnarray} /$$

[haz658]

My first question is how the authors were able to convert $ ln a_n /$ to $ (ln a_0 - \beta \varepsilon_n /$ , where a_n is the occupation number of the nth energy level,

[haz658]

Sorry. Still practicing.

$$ \frac {dlnW} {da_n} = 0 /$$ for the Boltzmann distribution

$$ a_n = Ne^{\alpha} e^{- \beta \varepsilon_n} /$$

$$ ln a_n = ln a_0 - \beta \varepsilon_n /$$