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Topic: Acid-Base Titration *delete me*  (Read 4018 times)

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Offline jh35

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Acid-Base Titration *delete me*
« on: October 08, 2008, 12:12:47 AM »
This question is bugging me.  It states:

Consider the titration of 30.0 mL of 0.030 M NH3 with 0.025 M HCl. The equivalence point is reached when 36 ml of HCl (titrant)is added.What is the pH at the equivalence point?
(Kb of NH3 = 1.8 x 10-05)

Please help.  And thanks.
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Offline Astrokel

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Re: Acid-Base Titration *delete me*
« Reply #1 on: October 08, 2008, 02:44:15 AM »
hi

you need to show some work.
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Offline jh35

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Re: Acid-Base Titration *delete me*
« Reply #2 on: October 08, 2008, 10:03:31 AM »
Quote from: Astrokel on October 08, 2008, 02:44:15 AM
hi

you need to show some work.

so you cannot show me a way to start it off?  or a process?  =(
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Offline Borek

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Re: Acid-Base Titration *delete me*
« Reply #3 on: October 08, 2008, 10:37:03 AM »
What will be present in the solution at equivalence point?
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