A 1.719 g sample of a CaCo3 mixture is thermally decomposed, evolving CO2. After the reaction, the mixture has a mass of 1.048 g
a. How many grams and moles of CO2 gas are evolved?
1.719 g - 1.048 = 0.671 g CO2
b. How many moles and grams of CaCO3 are in the mixture?
I'm not sure about this one..
0.0152 mole of CO2 * 1 mol CaCO3/ 1 mol CO2 = 0.0152 mol CaCO3
* 100.09 g CaCO3/ 1 mol CaCO3 = 1.52 g CaCO3
Is the formula for this problem CaCO3 ---- CaO +CO2??