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Author Topic: Synthesis of Hexaamminenickel (II) tetrafluoroborate  (Read 10024 times)

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rosco_pk

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Synthesis of Hexaamminenickel (II) tetrafluoroborate
« on: December 15, 2008, 01:55:46 PM »

Ok so i made a compund in a lab - Hexaamminenickel (II) terafluoroborate ( [Ni(NH3)6][BF4]2) from Nickel Chloride (NiCl2) reacting with aqueous ammonia (NH3) then with ammonium tetraflouroborate[NH4][BF4]. The intermediate being [Ni(NH3)6]Cl2.

I need to write a balanced equation so i can calculate the percentage yeild of my product. Anyone able to help me??? I came up with NiCl2 + NH3 + (NH4)(BF4) = Ni(NH3)6(BF4)2 + Cl2 but i dont think that is correct.
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AWK

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Re: Synthesis of Hexaamminenickel (II) tetrafluoroborate
« Reply #1 on: December 15, 2008, 07:02:22 PM »

Write down a double replacement reaction (metathesis) between nickel chloride and ammonium tetrafluoroborate first, then form a complex. Finally add both reaction
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n4k

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Re: Synthesis of Hexaamminenickel (II) tetrafluoroborate
« Reply #2 on: December 15, 2008, 11:33:51 PM »

 ;)this is reaction addition
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rosco_pk

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Re: Synthesis of Hexaamminenickel (II) tetrafluoroborate
« Reply #3 on: December 16, 2008, 12:47:57 PM »

thanks for the pointers.
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lekoala

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Re: Synthesis of Hexaamminenickel (II) tetrafluoroborate
« Reply #4 on: October 22, 2010, 12:41:48 AM »

I no this is from 2008 but I'm at uni and I just did this lab so Im posting the equation for other new students

[NA(NH3)6]Cl2 + 2NH4 + 2BF4 –> [Ni(NH3)](BF4)2 + 2Cl- + 2NH+4

voila
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