Mmm the proton on C-3 has a chemical shift of 7.6(or whatever that is) ppm. just by looking at it might appear to be a triplet, which is what you would expect since there are two protons on adjacent carbons, one on C-2 and one on C-4. But if you expand the aromatic region, you can see that the signal for H-3 is actually a doublet of doublets. it's coupled to H-2 and H-4. Since H-2 and H-4 are not identical, their interactions with H-3 are not identical,(in other word the value of 3JH-3,H-2 is not equal to the value of 3^JH-3,H-4)..the n+1 rule seems not to apply here.
If the value of 3^JH-3,H-2 were equal to that of 3^JH-3,H-4, then the peak for H-3 would be a triplet. And i think your 1H NMR has just done that!