[firedamage]

reaction between HCl and NaOH:
1)using a measuring cylinder,measure 45ml of 1 M HCL.pour into the reaction vessel and determine the temperature of the HCl.record this temperature on your report sheet.
2)measure 5ml of NaOH using another measuring cylinder.
3)Add NaOH to the HCl in the reaction vessel all at once and carefully stir the mixture withe the thermometer.record the highest temperature.

#When I add mix 30 ml of HCl with 25 ml of NaOH the temperature change is 5'C
#                mix 25 ml of HCl with 30 ml of NaOH the temperature change is also 5'C
#                mic 20 ml of HCl with 35 ml of NaOH the temperature change is 5'C
*Why the temperature change is the same??

[Vidya]

what is the molarity of NaOH solution?

[firedamage]

1 M NaOH and 1 M HCl

[Arkcon]

Can you use a formula, and some given constants, to determine how many kJ of heat the reaction between those amounts of NaOH and HCl can generate?  (I'm really asking you, can you? Because I don't have those formulas or constants handy, myself, right now.)  Can you use a formula for that amount of kJ and the heat capacity of water, to determine how many deg. C temperature change you should have seen?  Maybe the math will work out to 4.3, 4.5, and 5.2 dec C, and your accuracy is limited by your equipment and skill level.

[ARGOS++]

Dear firedamage;

With both solution as 1 molar it’s no surprise that the first two experiments give the identical temperature gain, because both have identical total mass and both have the identical reaction amount.

For the last experiment I calculated something around/above 4°C increase and so it depends very strongly on what precision/resolution the thermometer has you used during the experiments!

Good Luck!
                    ARGOS⁺⁺

[firedamage]

means tat the heat of neautralisation remain the same?

[ARGOS++]

Dear firedamage;

If you would do the simple "Stoichiometry  (#23'025)" you would find that the first both generate the same amount of heat for the identical total volume.

But for the third only 80% of the same heat will be generated.

Good Luck!
                    ARGOS⁺⁺