what is the Kb value for the base?
given:
0.120M weak base
pH=11.28
initially i thought about the equation
pH=pKa+log[base]
[acid]
so i did:
11.28=pKa+log(0.120)
pKa=12.20
pKa=-log Ka
10-12.20
Ka=6.31*10-13
Ka*Kb=Kw=1.0*10-14
Kb=.0158
this is not the answer, however.
please help me determine the answer