# Chemical Forums

• February 23, 2017, 09:42:15 AM
• Welcome, Guest

•

•

### Chemistry Books

Pages: [1]   Go Down

### AuthorTopic: Frequency Factor and Activation Energy?  (Read 15393 times) !function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0];if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src="https://platform.twitter.com/widgets.js";fjs.parentNode.insertBefore(js,fjs);}}(document,"script","twitter-wjs"); (function() {var po = document.createElement("script"); po.type = "text/javascript"; po.async = true;po.src = "https://apis.google.com/js/plusone.js";var s = document.getElementsByTagName("script")[0]; s.parentNode.insertBefore(po, s);})();

0 Members and 1 Guest are viewing this topic.

#### docpar

• Regular Member
• Mole Snacks: +0/-0
• Offline
• Posts: 9
##### Frequency Factor and Activation Energy?
« on: March 22, 2009, 01:51:48 PM »

Hi, I have a homework problem that I am having some problems understanding.

It goes like the following:

The decomposition of N2O5(ga) has the following rate constants at the four temperatures below:

T(k)     K
658    2.14x10^5
673    3.23x10^5
688    4.81x10^5
703    7.03x10^5

A)determine the activation energy as well as the frequency factor.
B)calculate the rate constant for 300k

For A, i got Ea=98853.46 J/mol and A=1.54x10^13
I used lnK= (-Ea/R)(1/T) + lnA
This equation is like the equation for a line, so i graphed all the values given above, and figured that the slope would be the activation energy (i did this because the problem required that I use all the data given).
To find A (frequency factor), i simply used a value from the data given in the equation K=Ae^-Ea/RT

B i got K=1.29x10^ -90
I used the formula K1/K2=e^(-Ea/R (1/T1)-(1/T2))

These all seem very wrong, are they? I dont know if i did them properly

Thanks for any *delete me*
Logged

Pages: [1]   Go Up

Mitch Andre Garcia's Chemical Forums 2003-Present.

Page created in 0.063 seconds with 23 queries.