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Author Topic: How to determine number of moles of electrons transferred in a reaction?  (Read 21128 times)

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jayjay112

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Hi,

please see my question at...http://www.flickr.com/photos/37144556@N07/3456365719/sizes/o/

G' = -nF. E'
G' = -RT. ln k

G' = (-8.314 x 298)( ln k )

0.32 = [(-8.314 x 298)( ln k )] / [(n) (96500)]

and then

(0.32).(n).(96500) / (-8.314 x 298) = ln k

but what is n (the number moles of elctrons transferred in the reaction )

is it 2?? because of the 2+???

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lancenti

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    • Crystal Spires

It's not part of the question, so you don't have to actually answer it but I'm guessing you're curious.

To answer your question, you simply need to construct the balanced half-equations. Either the Reduction or Oxidation Half-equation will be sufficient.

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jayjay112

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but do i not need "n" to solve for k??
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leve

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but what is n (the number moles of elctrons transferred in the reaction )

is it 2?? because of the 2+???[/b]

The charge does not necessarily mean the number of electrons. What are the reduction and oxidation reactions? Since you have your overall reaction in the question, how many moles of electrons are required to produce that reaction?
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jayjay112

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Since you have your overall reaction in the question, how many moles of electrons are required to produce that reaction?

Thats the part  i dont know???
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leve

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What are the reduction and oxidation reactions?
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jayjay112

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What are the reduction and oxidation reactions?

ok i dont know how to write them, ( ill learn) ..but when i learn how to what do i do?
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leve

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n is the number of electrons needed for the reaction. Balance both the reduction and oxidation reactions such that your overall reaction is the one in the question and the number of electrons canceled out is n.
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jayjay112

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thank you
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