[Koskesh]

Question:

What is the % yield of 0.112g S02 obtained from the combination of 0.0781g of CS2 according to the reaction CS2 + 3O2 --> CO2 + 2SO2

I know the equation is AY/TY X 100%. I'm pretty sure the actual yield is 0.112g S02 but what would the theoretical yield be I need for the denominator?

[Borek]

Calculate it from the reaction equation, this is a simple stoichiometry.

http://www.chembuddy.com/?left=balancing-stoichiometry&right=stoichiometric-calculations

[Dingle]

SO₂ is the limiting reagent obviously because O₂ from air is in excess.

Calculate the amount in moles of CS2 you started with and the moles of SO2 produced (you will need to work out their molecular weights from the periodic table to do this) and thus, since every 1 molecule of CS2 should give 2 molecules of SO2 (from your reaction equation) then the % yield = AY/TY x 100 = (moles of SO2 produced)/(2x starting moles of CS2) x 100 (%)

Hope this helps