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Topic: Barometric Pressure  (Read 6729 times)

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Offline CL

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Barometric Pressure
« on: September 10, 2009, 07:51:44 AM »
A barometer is filled with diethylene glycol (d = 1.118 g/cm^3). The liquid height is found to be 9.25 m. What is the barometric (atmospheric) pressure expressed in millimeters of mercury?

Thanks in advance for any help.  :)
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Offline Borek

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Re: Barometric Pressure
« Reply #1 on: September 10, 2009, 08:17:01 AM »
You have to show your attempts to receive help. This is a forum policy.
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Offline CL

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Re: Barometric Pressure
« Reply #2 on: September 10, 2009, 08:20:53 AM »
Quote from: Borek on September 10, 2009, 08:17:01 AM
You have to show your attempts to receive help. This is a forum policy.

I'm using the formula P = g x h x d, but I don't know how to express it into mmHg.
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Offline Borek

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Re: Barometric Pressure
« Reply #3 on: September 10, 2009, 08:33:12 AM »
Use given information to calulate pressure, than calculate height of mercury required to get the same pressure.
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Offline CL

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Re: Barometric Pressure
« Reply #4 on: September 12, 2009, 07:02:10 PM »
Quote from: Borek on September 10, 2009, 08:33:12 AM
Use given information to calulate pressure, than calculate height of mercury required to get the same pressure.

So..

P = g.h.d
P = 9.81 m.s^-2 * 9.25 m * 1118 kg/m^3
P = 1.015 x 10^5 Pa

Converting from Pascal to mmHg:

1.015 x 10^5 Pa * 760 mmHg/101325 Pa = 761.0 mmHg

Is this correct?
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Offline Borek

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Re: Barometric Pressure
« Reply #5 on: September 13, 2009, 03:47:06 AM »
Looks OK.
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