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Author Topic: Problem of the Week - 10/26/09  (Read 2665 times)
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azmanam
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« on: October 26, 2009, 03:30:20 PM »

This time, I'm not going to answer after every guess.  The community can discuss and combine and come back with a consensus answer.  I like that better than the 'is this right?' 'no.' 'how bout this?' 'sorta, think about it this way.' ... approach to problems.  So discuss and argue and debate amongst yourselves and let me know when you think you've got the answer.

QUESTION: Provide a complete, arrow pushing mechanism for the following transformation and predict the product:
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Heory
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« Reply #1 on: October 26, 2009, 08:45:32 PM »

No stereoselectivity in the reaction?
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Heory
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« Reply #2 on: October 27, 2009, 12:18:35 AM »

I prefer the old way of discussing, for few people are willing to post their viewpoints.
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azmanam
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« Reply #3 on: October 29, 2009, 02:31:03 AM »

It looks like you're right, no one wants to play my way.  Oh well.

There will be stereoselectivity issues to discuss later, but first we'll focus on just the arrow pushing.  You have chosen the wrong nucleophile after L.A. activation, and as a result, the rest of the mechanism is off track.  Reassess with a different nucleophile and see what else looks interesting.
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Dan
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« Reply #4 on: October 29, 2009, 04:44:48 AM »

This one's tough. I got to a tricyclic intermediate but I'm not sure where to go from there, or even whether I'm in the right place anyway...
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azmanam
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« Reply #5 on: October 29, 2009, 04:47:10 AM »

Diels Alder.  Interesting, but no.  (plus, I think the bottom face opposite the isopropyl group would be more accessible if that were to occur Smiley)
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« Reply #6 on: October 29, 2009, 05:17:22 AM »

For the first mechanism proposed - are there any mechanisms involving vinylic carbocations that are generally accepted?
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azmanam
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« Reply #7 on: October 29, 2009, 05:23:40 AM »

addition of HX to alkynes

http://www.chemistry.ccsu.edu/glagovich/teaching/311/content/alkyne/reactions/alkynerxn2.html
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Heory
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« Reply #8 on: October 29, 2009, 05:34:08 AM »

 Smiley
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Heory
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« Reply #9 on: October 29, 2009, 05:38:10 AM »

I'm really very sorry. Your drawing always looks rather beautiful and I just want mine to be better. Well, I will use the ACS style.
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nj_bartel
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« Reply #10 on: October 29, 2009, 05:38:29 AM »


Ah alright.  When I took organic I, that mechanism was presented to me as still pretty widely disputed due to the instability of that cation.  An alternative possibility presented was an X'onium intermediate.

Edit:  I like your new one Heory.
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azmanam
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« Reply #11 on: October 29, 2009, 06:18:18 AM »

I had no idea this question would be this intriguing.  Three completely different guesses with three completely different modes of activity, yet none of them get to the product of the reaction.  Very fun Smiley

Perhaps it would be useful to think about and list in words what the various functionalities of the two reagents are.  Then maybe try to think about how they might react with each other under lewis acidic conditions.  Look for best nucleophiles, best electrophiles and see if we can talk through it that way?

Heory: not sure what you're talking about.  Your schemes are nice and quite easy to follow.  Keep up the good work. (btw, I don't use ACS, I use TotSyn style, downloaded from here:  http://totallysynthetic.com/blog/?page_id=287)
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Heory
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« Reply #12 on: October 29, 2009, 06:29:58 AM »

I am totally confused...
OH is not a good nuleophilic reagent in the presence of LA
i need more clues
now it is 0:30 here and i must go to sleep
see you tomorrow
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azmanam
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« Reply #13 on: October 29, 2009, 06:33:16 AM »

Wink  see you tomorrow.  Let visions of terpenes dance in your dreams Smiley
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« Reply #14 on: October 29, 2009, 06:35:50 AM »

Diels Alder.  Interesting, but no.  (plus, I think the bottom face opposite the isopropyl group would be more accessible if that were to occur Smiley)

My structure also breaks Bredt's rule... Schoolboy error...

This is tough, I need more time to think about it. I'm liking Heory's diene nucleophile though.
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Heory
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« Reply #15 on: October 29, 2009, 09:50:14 AM »

the diene nucleophile is just like that in Prinse reaction, but here it may be a side reaction. if the answer was as simple as the acetal, i would be crazy Huh
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azmanam
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« Reply #16 on: October 29, 2009, 10:30:47 AM »

couldn't sleep? Smiley

haha.  all that functionality just for an acetal formation?  that would be an awesome trick question.  The acetal is the initial product of the diol/aldehyde/L.A.  Once formed, the diol will continue to react.  We're on the right track now.
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« Reply #17 on: October 29, 2009, 02:48:16 PM »

The acetal formation in this case is allowed to proceed to an appreciable extent due to the carbonyl oxygen coordination to the boron complex, yes?
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azmanam
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« Reply #18 on: October 29, 2009, 02:50:05 PM »

yup, lewis acid activation lowers the activation energy for addition to oxonium ions.  loss of water gets us to the acetal
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« Reply #19 on: October 29, 2009, 06:23:04 PM »

another guess:
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nj_bartel
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« Reply #20 on: October 29, 2009, 06:56:20 PM »

What's the leaving group in that last step?

O+-B--F3?
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Heory
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« Reply #21 on: October 29, 2009, 07:00:58 PM »

something was wrong and i'll think of it for some time
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Heory
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« Reply #22 on: October 29, 2009, 07:10:06 PM »

q
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azmanam
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« Reply #23 on: October 30, 2009, 01:36:53 AM »

nope Smiley. my hint for the second step of the mechanism: remember that acetals are in equilibrium
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Heory
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« Reply #24 on: October 30, 2009, 02:33:25 AM »

It's quite a difficult work to predict the product, because many paths exist for the reaction. If this is still not right, I'd like you to tell me more information about it.
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azmanam
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« Reply #25 on: October 30, 2009, 05:07:38 AM »

you've got the right transformation (which named reaction is this?), but the wrong regiochemistry.  why did you choose that c-c bond to make?
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« Reply #26 on: October 30, 2009, 07:28:23 AM »

Hmmm. Good work on the acetal Heory!

Something like this?

This terpene stuff is making me itch for a hydride shift... but I can't see a good oppertunity.
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« Reply #27 on: October 30, 2009, 07:51:39 AM »

that's the right C-C bond formation.  The orientation of the alkene-containing side chain will be dictated by steric clash with the isopropyl group... but the diene-containing 6-membered ring will not adopt a chair conformation, so we'll need to rethink the origin of selectivity in the c-c bond forming step (still need a name for this reaction).

The chemistry after the c-c bond forming step is not correct yet.  different things happening here.  getting closer Smiley
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« Reply #28 on: October 30, 2009, 11:57:59 AM »

 Smiley
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azmanam
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« Reply #29 on: October 31, 2009, 03:49:52 AM »

you're correct up to your last step.  Still looking for a name for the c-c bond forming step (and there will be a name for the final step).  you've got the right idea, but hydride doesn't transfer.  I think as a result of geometry, but I might have to look at a model.  anyway, we're quite close now.
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« Reply #30 on: October 31, 2009, 04:03:51 AM »

 Smiley
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azmanam
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« Reply #31 on: October 31, 2009, 04:38:05 AM »

There is certainly a lot of functionality in this system.  I'd wager the acetal is definitely the fastest process based on relative nucleophilicity of alcohols over alkenes.  From there, the 6-membered transition state in the Prins rxn[1] is fast due to proximity.  The pinacol[2] (good job on the naming, btw) occurs based on the chair geometry of the THP.  I believe only the alkyl group has sufficient overlap with the p-orbital to migrate.  While there is a lot of functionality, Overman sure tames it well, as the product is isolated in near 80% yield as a single isomer.[3]

The Prins-Pinacol is a recurring theme in the Overman lab, as they have numerous papers on the subject[4].  It is certainly a powerful too for building significant molecular complexity (3 new stereocenters and a new ring) on their way to Briarellin E.  Well done.

[1] http://www.organic-chemistry.org/namedreactions/prins-reaction.shtm
[2] http://www.organic-chemistry.org/namedreactions/pinacol-rearrangement.shtm
[3] http://dx.doi.org/10.1021/ja035445c (comm)
     http://dx.doi.org/10.1021/jo9010156 (full paper)
[4] for example:
     http://dx.doi.org/10.1021/jo0522862
     http://dx.doi.org/10.1021/jo034982c
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« Reply #32 on: October 31, 2009, 04:48:05 AM »

finally work it out! But it's quite a hard work for me to predict the product without any hints. How great overmann's idea is!
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« Reply #33 on: October 31, 2009, 08:02:08 PM »

BTW, I just started to learn organosilicon in my advanced organic chemistry class, and just after class this problem happened to occur to me, which made me itch for a reaction related to the silyl groups. However, the C≡C-TMS groups didn't react, so I get the concept that C≡C-TMS is not so active as C=C-TMS, which usually acts as a nucleophilic reagent.
I still have some doubt. When the alcohol OH bound to BF3, which weakened the B-F bond and released F- (in equilibration), why wasn't the protected alkyne or the hydroxyl deprotected? As we know, Si-F bond is one of the most strongest sigma bond. On the other hand, the resulted water would react with BF3 thus leading to the formation of HF and B(OH)3, which undoubtedly would not only make the two groups deprotected but also destroy the catalyst of the reaction. But it seems that water was not removed from the reaction system, why?
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« Reply #34 on: November 01, 2009, 01:14:02 AM »

But why does the tow hydroxyl group only one can take part in the reaction?
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Heory
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« Reply #35 on: November 03, 2009, 02:33:42 AM »

azmanam, could you please answer my questions? Thanks very much.
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azmanam
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« Reply #36 on: November 03, 2009, 02:45:34 PM »

re: heory, I don't have a great answer to your question, but I would not expect the equilibrium with F- to be very favorable.  We don't usually think of F- as a leaving group, at least not in the same way we think of Cl- or Br- or I- as leaving groups. 

Also of interest, I copied the question from Evans' problem database.  In Overman's actual papers, though, the published route uses tin tetrachloride.  so maybe sometime between the posting of the question to the database and the publication they did encounter such problems.  They also preform the acetal with PPTS and MgSO4 (to soak up the water), so the actual prins/pinacol pathway maintains anhydrous conditions.  I think your comments are quite insightful, but Overman does not seem to expand on the point much in either the comm or the full paper.

re: ulfsaar, I don't know.  You can form a diffrent 6-membered TS with the other olefin to give a tertiary carbocation... maybe sterics of that TS preclude that pathway.  Interesting question I don't have a good answer for off the top of my head.
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