[ding0]

A 12.0 gram piece of pure gold originally at 80°C is cooled and in the process releases 72.8 Joules of heat. What is the final temperature of the gold in degrees Celsius?

My answer: 33°C

My work:
Q=mc :delta:T
 :delta:T= Q/(mc)
Q= -72.8 J
m= 12 g
c= 0.129 J/(g*K)
:delta:T= ?

Plugged it all in the equation and I get: :delta:T= Q/(mc)= -47 Kelvin
 :delta:T=T_F -T_I
change in T = T final minus T initial where T is Temperature
T_F=  :delta:T+T_I
T_F= -47 K + 353 K = 306 K **80°C=353 K**
306 K = 33°C

My answer: 33°C


Correct?

[renge ishyo]

I did it and got the same number at least.

[Entrigued]

A 12.0 gram piece of pure gold originally at 80°C is cooled and in the process releases 72.8 Joules of heat. What is the final temperature of the gold in degrees Celsius?

My answer: 33°C

My work:
Q=mc :delta:T
 :delta:T= Q/(mc)
Q= -72.8 J
m= 12 g
c= 0.129 J/(g*K)
:delta:T= ?

Plugged it all in the equation and I get: :delta:T= Q/(mc)= -47 Kelvin
 :delta:T=T_F -T_I
change in T = T final minus T initial where T is Temperature
T_F=  :delta:T+T_I
T_F= -47 K + 353 K = 306 K **80°C=353 K**
306 K = 33°C

My answer: 33°C


Correct?

It is indeed correct. Good job, keep it up!