Not sure if this will help or not but...
When ANYTHING is put into water, there will be an 'equilibrium' involved. Water is called the 'universal solvent' for this reason (even though some things seem NOT to dissolve, they do, to a very small degree)
Anyways, when ethanol (C2H5OH) is put into water, a few different equilibrium could occur:
C2H5OH + H2O <==> C2H5OH2+ + OH-
which 'produces' a hydroxide (the easiest way to visualize basicity)
C2H5OH + H2O <==> C2H5O- + H3O+
where H3O+ is H2O with the classic H+, that you mentioned earlier, attached to it.
Technically speaking, both of these equilibria occur to some degree. One will occur more than the other - and so one of OH- or H+ will be more plentiful in the solution (as opposed to a perfectly neutral solution, where the exact same amount of each is present). If there is more OH-, then the pH will be basic (and the pH value will tell you exactly how much OH- there is) - on the other hand, if the pH is acidic then there is more H+ and you can figure the math of that out too, if you like.