As Schrödinger said, it is difficult to help without being able to see the whole full initial question.
But if you have
M = mol / L
And you put in the information you gave, you would need to multiply both side of the above equation by the volume (L) to get the mol of sodium carbonate.
Stoichiometry is then needed to convert that to grams, so you were right, you just did the math wrong to solve for the mol.
This seems like a titration problem though so it is probably not as simple as that, but I can't know without a clear initial problem.