[Sodium-Potassium Pump]

Hi, I need to make a solution of saccharin in the lab and am using a saccharin sodium salt which is water soluble.  I can't remember if I'm supposed to include the Na+ atomic weight for the molecular weight of the compound when calculating my molarity or not.  It's either 205.16 or 182.18.  Thanks for the *delete me*

[JGK]

For every 1.126g of saccharin (sodium salt) you weight it will contain 1 g saccharin.

[Sodium-Potassium Pump]

For every 1.126g of saccharin (sodium salt) you weight it will contain 1 g saccharin.

So you're saying don't include Na in my molecular weight when calculating the molarity of my solution?

[JGK]

Having the sodium salt just means you have wiegh more to get the required quantity of saccharin, the conversion factorbetween the two weieghts is calculated from the molecular weight ratio = (Sodium saccharin/saccharin)