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Author Topic: molarity  (Read 1312 times)

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Sambo

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molarity
« on: July 07, 2010, 09:47:52 AM »

Calculate the molarity of acetic acid in a vinegar sample, knowing that 5.00 mL of vinegar requires 43.50 mL of 0.105 M NaOH to just reach the phenolphthalein endpoint in a titration. I m having trouble with this. Thanks!
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AWK

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Re: molarity
« Reply #1 on: July 07, 2010, 09:26:10 PM »

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relike868

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Re: molarity
« Reply #2 on: July 08, 2010, 12:29:16 AM »

Some tips: number of moles =  Molarity*volume
and writing the following equation could be useful:
CH3COOH + NaOH = ??
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