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Author Topic: 20% aqueous sodium hydroxide (NaOH) - Need Help Understanding.  (Read 9667 times)

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Cavalier

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20% aqueous sodium hydroxide (NaOH) - Need Help Understanding.
« on: December 03, 2010, 05:12:09 AM »

Ok...  I took Chem classes, but that was quite a while ago.  I need some help understanding this statement....

"20% aqueous sodium hydroxide (NaOH)"

If I have dry crystal NaOH that I purchased from Home Depot, how do I turn that into 20% aqueous sodium hydroxide.  And in particular, how do I do this without dissolving my garage or kitchen.  Does the % mean by weight?  20 grams of NaOH for every 100 grams of water?

Thank you all in advance.

RC
« Last Edit: December 03, 2010, 05:37:47 AM by cavaliermills »
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Borek

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Re: 20% aqueous sodium hydroxide (NaOH) - Need Help Understanding.
« Reply #1 on: December 03, 2010, 11:21:26 AM »

20g of NaOH per 100g of SOLUTION, not water.
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bberti

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Re: 20% aqueous sodium hydroxide (NaOH) - Need Help Understanding.
« Reply #2 on: January 03, 2011, 01:05:00 PM »

Assuming your 20% is weight on weight, just add 80 grams of water (80 mL at 20 degrees Celsius) to 20 grams of NaOH.
You'll have [(20g NaOH) /(20g NaOH+80g water) ]*100 ==> 20g NaOH every 100g of solution.
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darko

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Re: 20% aqueous sodium hydroxide (NaOH) - Need Help Understanding.
« Reply #3 on: January 03, 2011, 11:53:48 PM »

Assuming your 20% is weight on weight, just add 80 grams of water (80 mL at 20 degrees Celsius) to 20 grams of NaOH.
You'll have [(20g NaOH) /(20g NaOH+80g water) ]*100 ==> 20g NaOH every 100g of solution.

if you atempt to add temperature in calculation (in this case is better not to), then is more precise 4oC, ;D

i think that is more imprtant to explain that it is egzothermic reaction
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vmelkon

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Re: 20% aqueous sodium hydroxide (NaOH) - Need Help Understanding.
« Reply #4 on: January 23, 2011, 11:36:22 AM »

Assuming your 20% is weight on weight, just add 80 grams of water (80 mL at 20 degrees Celsius) to 20 grams of NaOH.
You'll have [(20g NaOH) /(20g NaOH+80g water) ]*100 ==> 20g NaOH every 100g of solution.

if you atempt to add temperature in calculation (in this case is better not to), then is more precise 4oC, ;D

i think that is more imprtant to explain that it is egzothermic reaction

egzothermic or egg-zothermic. Nah, exothermic.
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darko

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Re: 20% aqueous sodium hydroxide (NaOH) - Need Help Understanding.
« Reply #5 on: January 24, 2011, 04:41:23 AM »

Assuming your 20% is weight on weight, just add 80 grams of water (80 mL at 20 degrees Celsius) to 20 grams of NaOH.
You'll have [(20g NaOH) /(20g NaOH+80g water) ]*100 ==> 20g NaOH every 100g of solution.

if you atempt to add temperature in calculation (in this case is better not to), then is more precise 4oC, ;D

i think that is more imprtant to explain that it is egzothermic reaction

egzothermic or egg-zothermic. Nah, exothermic.



 :-*
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Lord Ferrum

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Re: 20% aqueous sodium hydroxide (NaOH) - Need Help Understanding.
« Reply #6 on: January 25, 2011, 07:40:13 PM »

That's why it's easier to use moles per liter  ;)
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skbuncks

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Re: 20% aqueous sodium hydroxide (NaOH) - Need Help Understanding.
« Reply #7 on: January 26, 2011, 12:36:39 AM »

That's why it's easier to use moles per liter  ;)

Not if your doing it in your garage without access to a volumetric flask it isn't.

skb
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