April 26, 2024, 02:01:04 AM
Forum Rules: Read This Before Posting


Topic: Titration Problem  (Read 2599 times)

0 Members and 1 Guest are viewing this topic.

Offline Boxxxed

  • Full Member
  • ****
  • Posts: 203
  • Mole Snacks: +1/-0
Titration Problem
« on: December 13, 2010, 11:39:17 AM »
Calculate how many millilitres of an HCl solution (0.0503 M) are needed to fully titrate a solution made by mixing 25.2 mL of NaOH 0.0360 M and 16.8 mL of Na2CO3 0.0415 M.

What do I use the Na2CO3 for? Don't I just calculate how much HCl reacts with NaOH? Not sure how to start this problem. If someone could vaguely explain the steps I'd appreciate it.

Offline Hybrid

  • Regular Member
  • ***
  • Posts: 63
  • Mole Snacks: +3/-3
Re: Titration Problem
« Reply #1 on: December 13, 2010, 11:53:51 AM »
it so easy 1mole HCl for each NaOH and 2 moles for Na2CO3
MV (HCl) = MV (NaOH) + 2 MV (Na2CO3)


Offline Boxxxed

  • Full Member
  • ****
  • Posts: 203
  • Mole Snacks: +1/-0
Re: Titration Problem
« Reply #2 on: December 13, 2010, 12:31:30 PM »
I did the problem fine. I always have problems determining the reaction equation myself if it is not given.

Are there any exercises I can do to know how to formulate reaction equations with just the compounds given? It almost seems as if this knowledge should already be attained because I've never practiced synthesizing reaction equations and I study more than most.

Sponsored Links