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Topic: 2NH3->N2+3H2. Rate=k[NH3]/[H2], what is the mechanism?  (Read 5204 times)

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Offline sorry931

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2NH3->N2+3H2. Rate=k[NH3]/[H2], what is the mechanism?
« on: March 07, 2011, 02:19:07 PM »
The rate of the reverse Haber process is 2NH3 -> N2 + 3H2. The rate law is k[NH3]/[H2].What is the mechanism?

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Ammonia decomposes to form nitrogen gas and hydrogen gas. The rate law for the reaction is Rate=k[NH3]/[H2].
Devise a plausible mechanism for this reaction, taking into account both the balanced equation and the rate law.
Thanks guys!!!

Offline JustinCh3m

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Re: 2NH3->N2+3H2. Rate=k[NH3]/[H2], what is the mechanism?
« Reply #1 on: March 08, 2011, 06:55:16 PM »
you need to write out the "elementary steps" and arrange them in such a way that the rate-limiting step gives you the same rate law as rate = k[NH3]/[H2]

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