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Author Topic: Interpreting an NMR and IR chart and calculating an HDI given the formula  (Read 3733 times)

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unincom

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The formula is C9H10O2

I'm pulling my hair out over this I just can't get it to work. I know the two doublets around 7 are from an aromatic ring and the triplet near 1 seems to be a methyl, but I can't figure out what would make this work.

Any help is appreciated
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unincom

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IR chart
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orgopete

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Just following with what you suggest, what is left?

C9H10O2 - C6H4 = C3H6O2 - CH3 = C2H3O2

Check the integral, is there a CH2 group present? If so, then what are the possible fragments for this compound.
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Honclbrif

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The proton resonance around 10 ppm and a couple of the IR features are practicably screaming the name of one of the functional groups. Furthermore, if your methyl is a triplet, what does that mean about its neighbors? Where is the resonance of its neighbor? What features would put it there?
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azmanam

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