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Interpreting an NMR and IR chart and calculating an HDI given the formula
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Topic: Interpreting an NMR and IR chart and calculating an HDI given the formula (Read 8545 times)
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unincom
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Interpreting an NMR and IR chart and calculating an HDI given the formula
«
on:
March 23, 2011, 11:13:00 PM »
The formula is C
9
H
10
O
2
I'm pulling my hair out over this I just can't get it to work. I know the two doublets around 7 are from an aromatic ring and the triplet near 1 seems to be a methyl, but I can't figure out what would make this work.
Any help is appreciated
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unincom
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Re: Interpreting an NMR and IR chart and calculating an HDI given the formula
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Reply #1 on:
March 23, 2011, 11:13:30 PM »
IR chart
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orgopete
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Re: Interpreting an NMR and IR chart and calculating an HDI given the formula
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Reply #2 on:
March 24, 2011, 12:42:32 AM »
Just following with what you suggest, what is left?
C9H10O2 - C6H4 = C3H6O2 - CH3 = C2H3O2
Check the integral, is there a CH2 group present? If so, then what are the possible fragments for this compound.
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Honclbrif
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Re: Interpreting an NMR and IR chart and calculating an HDI given the formula
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Reply #3 on:
March 24, 2011, 01:47:53 PM »
The proton resonance around 10 ppm and a couple of the IR features are practicably screaming the name of one of the functional groups. Furthermore, if your methyl is a triplet, what does that mean about its neighbors? Where is the resonance of its neighbor? What features would put it there?
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azmanam
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Re: Interpreting an NMR and IR chart and calculating an HDI given the formula
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Reply #4 on:
March 24, 2011, 04:42:44 PM »
also try starting here:
http://www.chemicalforums.com/index.php?topic=33208.0
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Interpreting an NMR and IR chart and calculating an HDI given the formula