Chemical Forums

Please login or register.

Login with username, password and session length

Sponsored links

Pages: [1]   Go Down

Author Topic: Oxidation State of Nitrogen  (Read 1620 times)

0 Members and 1 Guest are viewing this topic.

amey

  • Very New Member
  • *
  • Mole Snacks: +0/-0
  • Offline Offline
  • Posts: 2
Oxidation State of Nitrogen
« on: June 12, 2011, 05:34:14 PM »

One mole of N2H4 loses 10 moles of electrons to form a new compound 'Y'. Assuming all N2 appears in the new compound, what is the oxidation state of nitrogen in the new compound?

Please help me to solve this. Thanks.
Logged

Vidya

  • Full Member
  • ****
  • Mole Snacks: +25/-45
  • Offline Offline
  • Gender: Female
  • Posts: 418
  • Online Chemistry and Organic Chemistry tutor
    • Chemistry Tutor
Re: Oxidation State of Nitrogen
« Reply #1 on: June 13, 2011, 01:02:03 AM »

calculate oxidation number of N in N2H4
If only N2H4 loses 10 electrons , oxidation state of each N should increase by 5 

amey

  • Very New Member
  • *
  • Mole Snacks: +0/-0
  • Offline Offline
  • Posts: 2
Re: Oxidation State of Nitrogen
« Reply #2 on: June 14, 2011, 12:48:04 AM »

Thanks. I got it.
Logged
Pages: [1]   Go Up
 

Mitch Andre Garcia's Chemical Forums 2003-Present.

Page created in 0.064 seconds with 23 queries.