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mole calculation (ammonium nitrate)

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Offline rayyau35

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mole calculation (ammonium nitrate)
« on: October 22, 2011, 08:39:03 AM »
Ammonium nitrate, NH4NO3, is used as a fertilizer and to manufacture explosives.How many atoms of nitrogen are in 0.665 mol of this substance? How many grams of ammonium nitrate supply this much nitrogen.

Anyone help me.Please. Show calculations.
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Offline Jeremy

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Re: mole calculation (ammonium nitrate)
« Reply #1 on: October 22, 2011, 09:35:35 AM »
You can see from the molecular formula that there are two moles of nitrogen atoms per mole of NH4NO3. So to find the number of nitrogen atoms in 0.665 mol, multiply it by 2 and then by Avagadro's number.

For the second question multiply the molecular mass by 0.665 mol.
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Offline argorb

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Re: mole calculation (ammonium nitrate)
« Reply #2 on: October 22, 2011, 09:43:21 AM »
Quote from: rayyau35 on October 22, 2011, 08:39:03 AM
Ammonium nitrate, NH4NO3, is used as a fertilizer and to manufacture explosives.How many atoms of nitrogen are in 0.665 mol of this substance? How many grams of ammonium nitrate supply this much nitrogen.

Anyone help me.Please. Show calculations.

Read this: http://www.chemicalforums.com/index.php?topic=52071.0 . It might help you. Come back with a post showing your progress on the problem.
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