Topic: kinetic energy? (E = 0.5mv^2) (Read 5432 times)

tjalfe89 · « **on:** November 12, 2011, 10:44:24 AM »

hello. Why is the Kinetic enegy not directly proportional with the velocity, but with v^2? If u fx multiply the velocity with 3 the kinetic enegy will be 4.5 times bigger. Why is that? :-)

LackOfFuel · « **Reply #1 on:** November 12, 2011, 01:23:55 PM »

What is the unit for energy? Joule?

Borek · « **Reply #2 on:** November 13, 2011, 05:49:33 AM »

Quote from: tjalfe89 on November 12, 2011, 10:44:24 AM

hello. Why is the Kinetic enegy not directly proportional with the velocity, but with v^2?

Because that's the way it is? It can be confirmed experimentally, it makes units consistent, what more do you need?

Jorriss · « **Reply #3 on:** November 14, 2011, 04:04:46 PM »

Work-Energy theorem may satisfy you, check it out.

http://en.wikipedia.org/wiki/Work_(physics)#Work_and_kinetic_energy

juanrga · « **Reply #4 on:** November 16, 2011, 03:35:20 PM »

Think also that velocity is a vector but Energy a scalar.

Topic: kinetic energy? (E = 0.5mv^2) (Read 5432 times)

tjalfe89

kinetic energy? (E = 0.5mv^2)

LackOfFuel

Re: kinetic energy? (E = 0.5mv^2)

Borek

Re: kinetic energy? (E = 0.5mv^2)

Jorriss

Re: kinetic energy? (E = 0.5mv^2)

juanrga

Re: kinetic energy? (E = 0.5mv^2)

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Topic: kinetic energy? (E = 0.5*m*v^2) (Read 5432 times)

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Topic: kinetic energy? (E = 0.5mv^2) (Read 5432 times)