I just want to know if my approach and thinking is correct. Please Do NOT flat out tell me the answer.
Reaction 1 = benzoic acid + 1.0 M NaOH
-There is water in this solution as well I presume. NaOH forms hydroxide ions which deprotonate benzoic acid making it polar and thus soluble in water which is a polar compound.
Reaction 2 = conjugate base of benzoic acid + 6.0 M HCl
-How does hydronium form? Is it just reacting with NaOH to reach acid/base equilibrium?
Reaction 3 = Ethyl 4-Aminobenzoate + 1.0 M HCl
-Ethyl 4-Aminobenzoate is protonated by Hydronium which forms when HCl and H2O reach acid base equilibrium. The protonated compound is soluble in water?
Reaction 4 = Deprotonation of Amoniumbenzoate + 6.0 M NaOH
-When NaOH is added, lots of OH forms and makes the solution basic and the compound is deprotonated making precipitate out of solution?